(2x+5)(3x^2-20x+25)=0

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Solution for (2x+5)(3x^2-20x+25)=0 equation: 


Simplifying
(2x + 5)(3x2 + -20x + 25) = 0

Reorder the terms:
(5 + 2x)(3x2 + -20x + 25) = 0

Reorder the terms:
(5 + 2x)(25 + -20x + 3x2) = 0

Multiply (5 + 2x) * (25 + -20x + 3x2)
(5(25 + -20x + 3x2) + 2x * (25 + -20x + 3x2)) = 0
((25 * 5 + -20x * 5 + 3x2 * 5) + 2x * (25 + -20x + 3x2)) = 0
((125 + -100x + 15x2) + 2x * (25 + -20x + 3x2)) = 0
(125 + -100x + 15x2 + (25 * 2x + -20x * 2x + 3x2 * 2x)) = 0
(125 + -100x + 15x2 + (50x + -40x2 + 6x3)) = 0

Reorder the terms:
(125 + -100x + 50x + 15x2 + -40x2 + 6x3) = 0

Combine like terms: -100x + 50x = -50x
(125 + -50x + 15x2 + -40x2 + 6x3) = 0

Combine like terms: 15x2 + -40x2 = -25x2
(125 + -50x + -25x2 + 6x3) = 0

Solving
125 + -50x + -25x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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